|H. E. Smith||Spring 2000|
|Physics 1B - Tutorial #6|
Ceq = C + C/3 = 2.67µF
Q(top) = Q(right) = Q(bottom) CVAB/3 = 6.67 x 10-6C
The charge remains the same, but you are doing work pulling the plates apart, increasing the potential energy stored in the capacitor, PE = Q2/2C, where C = A/l has decreased becaused "l" has increased. Same charge, greater energy --> "bigger" spark.
If "h" is greater the flow of water will be greater; The change in PE is greater so the velocity will be greater. Remember Bernoulli?
The flow will go as the cross-sectional area of the pipes ~ d2
If the length of the pipes were increased, with the same vertical drop, then the flow of water would decrease because there would be greater drag.
What would happen if you put in two parallel pipes of the same length &
You would double the flow.
What would happen if you doubled the length of the pipe? You would decrease the flow.
What does this have to do with electricity?
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